执行下面C++代码可以找出千位与个位的和恰好等于中间两位的四位数，横线处应该填入（ ）int count = 0; int a, bc, d, tmp; for (int i = 1000; i <= 9999; i++) { a = (tmp = i) / 1000; ___________________ bc = tmp / 10; d = tmp - bc * 10; if ( a + d == bc) { count++; } } cout << count;
A. tmp = i / 10;
B. tmp = i % 100;
C. tmp -= a * 1000;
D. tmp = i - i%1000;
正确答案：C
试卷来源：202512 CCF-GESP编程能力等级认证C++一级真题